Tuesday, January 22, 2013

LED Flasher 2

Normally one LED bulb will take about 12mA and 2.5V.But in this circuit it will need only 1.5v and 1.5mA to flash 4 LED Bulbs.LM 3909 double up the voltage and store it in the Capacitor. Then the Capacitor discharge the stored voltage through the LED Bulbs with in a short period of time. This is how this Circuit is working. In this circuit 4 LED Bulbs will flash every 1.5 seconds.

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